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Calculate the quantity of heat produced in a 20Ω resistor carrying 2.5A current in 5 minutes. |
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Answer» Given : R = 20, I = 2.5A t = 5minutes = 5 x 60 = 300s Quantity of heat produced is given as H = I2 x R x t = (2.5)2 x 20 x 300 ∴ H = 37500J Heat generated H = I^2RT=2.5^2*20*5*60=37.5kJ |
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