1.

Calculate the quantity of ferrous and ferric ions that would be deposited by 1 faraday."(F = 56)"

Answer»

SOLUTION :1 mole of ELECTRICITY (i.e., 1 faraday) produces 1 EQ. of matter.
Mole of electric charge = 1 faraday (given).
`THEREFORE`. No. of equivalent of `Fe^(2+) = 1`.
and no. of equivalent of `Fe^(3+) = 1`.
`therefore` wt. of `Fe^(2+) = 1 XX (56)/(2)g = 28 g ""` (wt. = eq. `xx` eq. wt.)
and wt. of `Fe^(3+) = 1 xx (56)/(3) g = 18.6g`


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