1.

Calculate the product of uncertainity in position and uncertainity in velocity for an electron of mass 9.1xx10^(-31)kg. According to Heisenberg's uncertainty principle. (h=6.6xx10^(-34)kgm^(2)s^(-1),pi=3.14):-

Answer»

`5.8xx10^(-5)m^(2)s^(-1)`
`5.8xx10^(-5)cm^(2)s^(-1)`
`0`
`5.8xx10^(-9)m^(2)s^(-1)`

SOLUTION :According to heisenberg's uncertainty principle
`Deltax xxDeltaV=(h)/(4pim)`
`Deltax xxDeltaV=(6.6xx10^(-34)KGM^(2)s^(-1))/(4xx3.14xx9.1xx10^(-31)KG)`
`=5.8xx10^(-5)m^(2)s^(-1)`.


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