1.

Calculate the pressure exerted by 10^(23) gas molecules each of mass 10^(22) g in a container of volume one litre. The nms speed is 10^(5) cm sec^(-1).

Answer»

SOLUTION :No. of MOLECULES of gas `=10^(23)`
mass of one molecules `=10^(-22) g`
`V=1" LITRE "=10^(23) cm^(3)`
`U_("rms")=10^(5)` cm/sec
From kinetic equation
`PV =((1)/(3)) mnu^(2)`.
`P XX 1 =((1//3)xx10^(23)xx10^(-22)xx(10^(5))^(2))/(10^(3))`
`therefore P=-3.3xx10^(7)" dyne cm"^(-2)`


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