1.

Calculate the potentialcorresponding to the following cell Pt|Co^(2+)(2.0 M),Co^(3+)(0.01 M||Cr^(3+)(0.5M) Cr_(2)O_(7)^(2)(4.0 M),H^(+)(1.5 M)|Pt Given E_(Co^(2+)//Co^(3+))^(2)=-1.82 V, E_(Cr_(2)O_(7)^(2)-//Cr^(3))^(2)=+1.33 V

Answer»

`-0.32 v`
`+0.32 V`
`-0.44 v`
`+0.44 V`

Solution :`CO^(2+) rarr Co^(3+) +e^(-)xx6`
`14 H^(+) +Cr_(2)O_(7)^(2-) +6E^(-) rarr 2Cr^(3+)+7 H_(2) O`
`6Co^(2+) +14 H^(+) +Cr_(2) O_(7)^(2-) rarr 6Co^(3+) +2 Cr^(3+) +7 H_(2)O`
`E_(cell)^(@)=-1.82 +1.33 V==-0.49`
`=- 0.49 -(0.0591)/(6)LOG [10^(-2)]^(6)/([2.0]^(6)[4.0][1.5]^(14))=0.32 V`


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