1.

Calculate the potential of the following cell reaction at 258 K Sn^(4+)(1.50 M)+Zn(s) to Sn^(2+)(0.5 M) +Zn^(2+)(2.0 M) Standard potential of the cell is 0.89 v. s

Answer»

Solution :For the reaction :
`SN^(4+)(aq)+Zn(s) to Sn^(2+)(aq)+Zn^(2+)(aq)`
Accordingto Nernst EQUATION,
`E_(cell)^(@)=E^(@)-(0.0591)/(n)"LOG"([Sn^(2+)][Zn^(2+)])/([Sn^(4+)])`
`=0.89-(0.0591)/(2)"log"((0.5)(2.0))/((1.50))`
`=0.89-(0.0591)/(2)"log "0.667=0.89-0.0295xx(-0.1759)`
`=0.89+0.005=0.895" V "`


Discussion

No Comment Found

Related InterviewSolutions