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Calculate the potential of hydrogen electrode in contact with a solution whose pH=10. |
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Answer» SOLUTION :`H^(+)+E^(-)rarr1//2H_(2)n=1` `E=E''-(0.0591)/(n)LOG.(1)/([H^(+)])` `E=0-(0.0591)/(1)xxpH` `E=-0.0591xx10v` `E=-0.591//V` |
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