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Calculate the potential corresponding to the following cell. Given `Pt|Co^(2+)(2.0M),Co^(3+)(0.01M)||Cr^(3+)(0.5M),Cr_(2)O_(7)^(2-)(4.0M),H^(o+)(1.5M)|Pt ` `E^(c-)._(Co^(2+)|Co^(3+))=-1.82V` `E^(c-)._(Cr_(2)O_(7)^(2-)|Cr^(3+))=+1.33V` |
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Answer» `Co^(2+)rarr Co^(3+)+e^(-)]xx6` `14H^(o+) +Cr_(2)O_(7)^(2-)+6e^(-)rarr2Cr^(3+)+7H^(2)O` `ulbar(6Co^(+2)+14H^(o+)+Cr_(2)O_(7)^(2-)rarr6Co^(+3)+2Cr^(3+)+7H_(2)O)` `E^(c-)._(cell)=-1.82+1.33V=-0.49` `E_(cell)=E^(c-)._(cell)-(0.0591)/(6)log.([Co^(3+)]^(6)[Cr^(3+)]^(2))/([Co^(2+)]^(6)[Cr_(2)O_(7)^(2-)][H^(o+)]^(14))` `=-0.49-(0.0591)/(6)log.([10^(-2)]^(6)[0.50]^(2))/([2.0]^(6)[4.0][1.5]^(14))=-0.32V` |
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