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Calculate the pOH of a solution at 25^(@)C that contains 1 xx 10^(-10) M of hydronium ions, i.e., H_(3)O^(+) |
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Answer» <P>`7.000` `pH = -LOG[H^(+)], pH = -log[1 xx 10^(-10)]`, `pH = + 10 log 10, pH = 10` We KNOW that, `pH + pOH = 14`....(i) Put the value of pH in EQ. (i) `10 + P^(OH) = 14` `F^(OH) = 4`. |
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