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Calculate the pH of the following solutions: (a) 2g of TlOH dissolved in water to give 2 litre of solution. (b) 0. 3 g of dissolved in water to give 500 mL of solution. (c) 0. 3 g of NaOH dissolved in water to give 200 mL of solution. (d) 1 mL of 13.6 M HCl is diluted with water to give 1 litre of solution. |
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Answer» is a base,PH = 14-2.344 = 11.65b) Ca(OH)2 is a base,POH = POH = -log(0.0081) = 2.09PH = 14-POH =11.91c) NAOH is a base,POH = -log(0.0375) = 1.426PH = 14 - POH = 12.68d) HCL is a STRONG acid,pH = -log([TEX]{1.36\times 10^{-2}}[\tex]) = 1.88 |
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