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Calculate the pH of a solution containing 0.1 M `CH_(3)COOH` and 0.15 M `CH_(3)COO^(-)`. `(K_(a) "of" CH_(3)COOH=1.8xx10^(-5))`A. 9.1B. 3.9C. 10 .D. 4 .91 |
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Answer» Correct Answer - D pH of acidic buffer solution is `pH=pKa+ "log" ({"salt"})/({Acid})` ` Ka=1.8xx10^(-5)` pKa = 5 - log 1.8 =5 - 0.25 `pH=4.75+log(0.15)/(0.1)` `=4.75+ log 1.5` = 4.90 |
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