1.

Calculate the pH of 1.5 times 10^-3 M solution of Ba(OH)_2.

Answer»

SOLUTION :`Ba(OH)_2toBa^(2+)+2OH^(-)`
`1.5 times10^-3M 2 times1.5 times10^-5M`
`[OH^-]=3 times10^-3M`
`[becausepH+pOH=14]`
`pH=14-pOH`
`pH=14-(-LOG[OH^-])`
`=14+log[OH^-]`
`=14+log(3 times10^-3)`
`=14+log3+log10^-3`
`=14+0.4771-3`
`=11+0.4771`
pH=11.48


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