1.

Calculate the pH of 0.1 M CH_3 COOH solution.Dissociation constant of acetic acid is 1.8xx10^(-5) M.

Answer»

Solution :For WEAK ACIDS,
`[H^+]=sqrt(K_axxC)`
`=sqrt(1.8xx10^(-5)xx0.1)=sqrt(1.8xx10^(-6))`
`=1.34xx10^(-3)M`
`therefore pH=-LOG[H^+]=log(1.34xx10^(-3))`
`therefore pH=2.87`.


Discussion

No Comment Found