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Calculate the pH of 0.1 M CH_3 COOH solution.Dissociation constant of acetic acid is 1.8xx10^(-5) M. |
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Answer» Solution :For WEAK ACIDS, `[H^+]=sqrt(K_axxC)` `=sqrt(1.8xx10^(-5)xx0.1)=sqrt(1.8xx10^(-6))` `=1.34xx10^(-3)M` `therefore pH=-LOG[H^+]=log(1.34xx10^(-3))` `therefore pH=2.87`. |
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