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Calculate the pH of 0.001 M HCl solution. |
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Answer» Since HCl is a strong acid, it dissociates HCl → H+ + Cl- [H+] = [HCl] = 0.001 M [H+] = 1 × 10-3 M pH = -log[H+] = -log[1 × 10-3] pH = 3 |
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