1.

Calculate the pH of 0.001 M HCl solution.

Answer»

Since HCl is a strong acid, it dissociates

HCl → H+ + Cl- 

[H+] = [HCl] = 0.001 M

[H+] = 1 × 10-3 M

pH = -log[H+]

= -log[1 × 10-3]

pH = 3



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