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Calculate the pH at the equivalence point when a solution of 0.01 M CH_(3)COOHis titrated with a solution of 0.01 M NaOH.pKa of CH_(3)COOH is 4.74

Answer»


Solution :`CH_(3)COOH + NAOH Let acid be = V ML
VmL of 0.01 M `CH_(3)COOH` will require V ml of 0.01 mL NaOH. But `CH_(3)COONa` formed will make solution alkaline due to hydrolysis
`CH_(3)COONa = 0.01/2 = 0.005` M
USING EQUATION for PH of salt of weak acid and strong base.
`pH = 7 + (pK_(a))/2 + (log C)/2 = 7 + (4.74)/2 + (log 0.005)/2`
= 8.22


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