Calculate the period of oscillation of a body falling freely inside the tunnel created along the diameter of theearth. Given average density of the material of the Earth 5500kgm^(-3) and universal gravitational constant 6.67xx10^(-11)Nm^(2)kg^(-2).

Calculate the period of oscillation of a body falling freely inside th

1.	Calculate the period of oscillation of a body falling freely inside the tunnel created along the diameter of theearth. Given average density of the material of the Earth 5500kgm^(-3) and universal gravitational constant 6.67xx10^(-11)Nm^(2)kg^(-2).
Answer» Solution :We KNOW that time PERIOD of oscillation of a body dropped in the tunnel, `T=sqrt((3pi)/(Grho))` `"i.e."T=sqrt((3xx3.142)/(6.67xx10^(-11)xx5500))=sqrt((0.2567)/(10^(-8)))=0.5069xx10^(4)s=5069s` `T="1 hr 24 min 29 sec"`