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Calculate the percentage of free SO_(3)in an oleum ( considered as a solution of SO_(3)in H_(2)SO_(4)) thatis labelled109 %H_(2)SO_(4) . |
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Answer» SOLUTION :109 % `H_(2)SO_(4)` refersto the total massof pure `H_(2)SO_(4)`i.e ., 109 G that will be formed when 100 g ofoleum is dilutedby 9g of `H_(2)O ` which`(H_(2)O)` COMBINES with all the free `SO_(3)` present in OLEUM to form `H_(2)SO_(4)` `H_(2)O+SO_(3) to H_(2)SO_(4)` 1 mole of `H_(2)O` combines with 1 moleof `SO_(3)` or 18 g of `H_(2)O ` combines with 80 g of `SO_(3)` or 9 gof `H_(2)O `combines with 40 g of `SO_(3)` Thus , 100 g of oleum contains 40 gof `SO_(3)`or oleum 40 % of free `SO_(3)` |
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