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Calculate the percentage amount of oxalate in a given sample of oxalatesaltwhen 0.3 g of salt was dissolved in 100 mL and 10 mLof which required 8 mLof N/20 KMnO_(4)solution. |
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Answer» SOLUTION :Let the AMOUNT of oxalate in the sample be x g . Now , m.e of `KMnO_(4) = 1/20 xx 8 = 0.4 "" ` …(Eqn.1) ` :. ` m.e of 10 mL of oxalate salt solution = 0.4..(Eqn.2) ` :. ` m.eof 100 mL of oxalatesolution = 4.0 but m.e of oxalate = m.e of oxalate salt = 4 ...(Eqn . 7) ` :. ` equivalent of oxalate = `4/1000= (0.04) ` ....(Eqn.3) Wt . of oxalate ` = (0.004 xx 44 ) g ` ` = 0.176 g` ` {" eq. wt of " C_(2)O_(4)^(2-)= 88/2 = 44}` Percentage amount of oxalate = `(0.176 )/(0.3) xx 100 = 58.67 ` % |
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