1.

Calculate the overall order of a reaction which has the rate expression. (a) Rate= k[A]^(1//2) [B]^(3//2) (b) Rate= k[A]^(2//2) [B]^(-1) (c ) Rate= k[A]^(1//2) [B]^(-1) Rate= [A]^(X)[B]^(Y) = Order= x + y

Answer»

Solution :(a) Rate ` = k[A]^(1//2)[B]^(3//2)` ORDER ` = (1)/(2) + (3)/(2) = 2`
(b) Rate` = k[A]^(3//2)[B]^(-1)`Order ` = (3)/(2) - 1 = (1)/(2)`
(c ) Rate ` = k[A]^(1//2)[B]^(2) = 2.5`


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