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Calculate the osmotic pressure of a 0.1 M monobasic and if its pH is 2.0 at 25^(@)C. |
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Answer» <P> Solution :`{:(,HA,hArr,H^(+),+,A^(-)),("INITIAL","C mol L"^(-1),,,,),("At. eqm.",""C-Calpha,,""Calpha,,"Calpha):}``""(alpha = " degree of dissociation")` `"i.e."[H^(+)]=C alpha. " But "[H^(+)] = 10^(-2)M` `therefore""Calpha =10^(-2) or alpha =(10^(-2))/(C)=(10^(-2))/(0.1)=0.1` Total number of particles after dissociation `=C-C alpha + C alpha+ C alpha=C(1+alpha)` `therefore"van't Hoff factor (i)"=(C(1+alpha))/(C)=1+alpha=1+0.1=1.1` `therefore"Osmotic PRESSURE (P) = i CRT = "1.1xx0.1xx0.0821 xx 298 atm = 2.69 atm.` |
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