Calculate the osmotic pressure of 5 urea solution at 25 degree c

1.	Calculate the osmotic pressure of 5 urea solution at 25 degree c
Answer» Answer: Explanation: OSMOTIC presuure=i∗C∗R∗T where, C=concentration of solute(in terms of Molarity) R= GAS constant =0.082L(atm)(mol)−1K−1 T=temperature (in Kelvin) i=Van’t-Hoff factor(=1 for non-electrolyte) 5% urea solution means 5G urea is present in 100ml of solution. mole of urea=weight given/Molecular weight of urea =5g60gmol−1=112 Hence Concentration of urea (in terms of Molarity) = (moles of urea(n) /VOLUME of solution ) ×1000 ={(112)/100}∗1000 =1012 Hence Osmotic pressure =1×(10/20)×0.082×300 atm =20.52atm MARK BRAINLIEST PLZZZZZZZZZZZ

Answer»

Answer:

Explanation:

OSMOTIC presuure=i∗C∗R∗T

where, C=concentration of solute(in terms of Molarity)

R= GAS constant =0.082L(atm)(mol)−1K−1

T=temperature (in Kelvin)

i=Van’t-Hoff factor(=1 for non-electrolyte)

5% urea solution means 5G urea is present in 100ml of solution.

mole of urea=weight

given/Molecular weight of urea

=5g60gmol−1=112

Hence Concentration of urea

(in terms of Molarity)

= (moles of urea(n) /VOLUME of solution ) ×1000

={(112)/100}∗1000

=1012

Hence Osmotic pressure =1×(10/20)×0.082×300 atm

=20.52atm

MARK BRAINLIEST PLZZZZZZZZZZZ

Discussion