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Calculate the osmotic pressure of 0.05% urea solution in water at 20^(@)C. Given R = 0.0821 atm mol^(-1)K^(-1) . Molar mass of urea = 60 g mol^(-1) . |
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Answer» Solution :`pi ` = CRT = `("no. of moles")/("volume") xx R xx T` `= (W_(B))/(M_(B)) xx (RT)/(V)` = `(0.05)/(60) xx (0.0821 xx 293)/(100)` `pi` 0.0002 ATM. |
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