1.

Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37^(@)C.

Answer»

Solution :It is given that :
Volume of water, `V = 450 ML = 0.45 L` ,
Temperature, `T=(37+273)K = 310 K`
NUMBER of the polymer,
`n = (1)/(185000)`
We know that,
OSMOTIC PRESSURE, `X = (n)/(V)RT`
`= (1)/(185000)mol xx (1)/(0.45 L)xx 8.314xx10^(3)`
Pa. L. `K^(-1)mol^(-1)xx310 K`
= 30.96 Pa (approximately)


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