1.

Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymers of molar mass 185,000 in 450 mL of water at 37^(@)C.

Answer»

Solution :`pi=CRT=(n)/(V)"RT"`
Here, NUMBER of MOLES of solute dissolved `(n)=(1.0g)/("185,000 g mol"^(-1))=(1)/("185,000 g mol")`
`"V = 450 mL = 0.450 L,T = "37^(@)C= 37+273=310K`
`R = "8.314 KPA L K"^(-1)"mol"^(-1)=8.314xx1^(3)" pA L K"^(-1)"mol"^(-1)`
Substituting these values, we get
`pi=(1)/(185,000)"mol"xx(1)/(0.45 L)xx8.314xx10^(3)" Pa L K"^(-1)"mol"^(-1)xx310 K=30.96 Pa.`


Discussion

No Comment Found

Related InterviewSolutions