1.

Calculate the OH– concentration and the H_3PO_4 concentration of a solution prepared by dissolving 0.1 mol of Na_3PO_4 in sufficient water to make 1 l of solution K_(1)=7.1 xx 10^(-3), K_(2)=6.3 xx 10^(-8), K_(3)=4.5 xx 10^(-13))?

Answer»

`[OH^(-)] 3.73 xx 10^(-18) M, [H_(3)PO_(4)]=6 xx 10^(-3)M`
`[OH^(-)] 3.73 xx 10^(-4) M, [H_(3)PO_(4)]=6 xx 10^(-22\)M`
`[OH^(-)] 3.73 xx 10^(-2) M, [H_(3)PO_(4)]=6 xx 10^(-18)M`
`[OH^(-)] 3.73 xx 10^(-4) M, [H_(3)PO_(4)]=6 xx 10^(-16)M`

ANSWER :C


Discussion

No Comment Found