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Calculate the number of water molecule present in one drop of water which weights 0.18 g inplease answer me...then i will follow you.​

Answer»

Answer:

W= 0.18 G

M of H2O= 18 g (mass)

∴n = 0.18/18 = 0.01 (MOLES)

1 mole contains 6.023×10²³ molecules

∴0.01 mole contains (6.023×10²³)×0.01 = <U>6.023×10^21 molecules

Hope this helps u.....



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