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Calculate the number of water molecule present in one drop of water which weights 0.18 g inplease answer me...then i will follow you. |
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Answer» Answer: M of H2O= 18 g (mass) ∴n = 0.18/18 = 0.01 (MOLES) 1 mole contains 6.023×10²³ molecules ∴0.01 mole contains (6.023×10²³)×0.01 = <U>6.023×10^21 molecules Hope this helps u..... |
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