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Calculate the number of unpaired electrons in Ti^(3+), Mn^(2+) and calculate the spin only magnetic moment. |
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Answer» Solution :`Ti^(3+)` Ti (Z = 22). Electronic CONFIGURATION [Ar] `3D^(2)4s^(2)` `Ti^(3+)` - Electronic configuration `[Ar]3d^(1)` So, the number of UNPAIRED electrons in `Ti^(3+)` is equal to 1. Spin only magnetic moment of `Ti^(3+) = SQRT(1(1+2)) = sqrt(3) = 1.73 mu_(B)` `Mn^(2+)` Mn (Z = 25). Electronic configuration `[Ar] 3d^(5) 4s^(2)` `Mn^(2+)` - Electronic configuration `[Ar]3d^(5)` `Mn^(2+)` has 5 unpaired electrons. Spin only magnetic moment of `Mn^(2+) = sqrt(5(5+2)) = sqrt(35) = 5.91 mu_(B)` |
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