1.

Calculate the number of unpaired electrons in the following gasesous ions: Mn^(3+), Cr^(3+), V^(3+) and Ti^(3+). Which one of these is the most stable in aqueous solution?

Answer»

Solution :`Mn^(3+): 3d^(4) 4s^(0) rArr 4` unpaired electrons
`Vr^(3+) : 3d^(3) 4s^(0) rArr 3` unpaired electrons
`V^(3+) : 3d^(2) 4s^(0) rArr 2` unpaired electrons
`Ti^(3+): 3d^(1) 4s^(0) rArr 1` unpaired electrons
`CR^(3+)` is most stable as it has half filled `t_(2g)` ORBITALS.


Discussion

No Comment Found