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| 1. |
Calculate the number of unpaired electrons in the following gaseous ions : Mn^(3+),Cr^(3+),V^(3+) and Ti^(3+) Which one of these is the most stable in aqueous solution ? |
| Answer» Solution :`Mn^(3+):3D^(4)` has 4 UNPAIRED electrons, `Cr^(3+):3d^(3)` has 3 unpaired electrons, `V^(3+):3d^(2)` has 2 unpaired electrons, `Ti^(3+):3d^(1)` has 1 unpaired electron. `Cr^(3+)` is most stable out of these in aqueous solution because it has half-filled `t_(2g)` LEVEL (i.e., `t_(2g)^(3)`). | |