1.

Calculate the number of sodium ions that are present in 212g of sodium carbonate.

Answer»

Given: 

Mass of sodium carbonate = 212g 

Sodium carbonate is Na2CO3 

First, we need to calculate the number of moles of sodium carbonate we have in a 212g sample. To calculate this, we will ind the molar mass of sodium carbonate (Na2CO3 ): 

⇒ 2 × Molar mass of sodium + Molar mass of carbon + 3×molar mass of oxygen 

⇒ 2 × 23 + 12 + 3 × 16 

⇒ 46 + 12 + 48 

⇒ 106g/mol 

Thus, the molar mass of Na2CO3 is 106g/mol. 

Now we will calculate total number of moles by applying the

formula given:

Number of moles = \(\frac{Mass\,of\,sodium\,carbonae}{Molar\,mass\,of\,sodium\,carbonate}\)

 Number of moles = \(\frac{212g}{106g/mol}\)

⇒ 2 mol 

Now, we know that every mole of Na2CO3 have 2 moles of Na+ ions.Hence, total moles of Na2CO3 is 4 moles

Number of ions present = 6.022 × 1023 × 4mol = 24.088 × 1023 ions


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