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Calculate the number of particles present per unit cell in a B.C.C unit cell |
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Answer» SOLUTION :No. of ATOMS present in a body centered cube = (No. of corner atoms) `xx` (Share of each corner atoms per unit cell) + (No. of atoms at the center of the body) `xx` (Share of body centered atom per unit cell) `= 8 xx (1)/(8) + 1` `= 1+1 = 2` atoms per unit cell. DETAILED Answers. No. of particles present per unit cell in B.C.C. unit cell `= 8 xx (1)/(8) + 1 = 2`. |
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