1.

Calculate the number of neutrons in the remaining atom after emission of an alpha particle from 92^(X^(238)) atom. also report the mass number and atomic number of the product atom.

Answer»

Solution :`92^(X^(238)) rarrA^(X^(m))+2^(He^(4))`
comparing mass NUMBER of both sides
238 =m+4
m=238-4 =234
comparingatomicnumberon both sides
92=A+2
A=92-2 =90
X hasatomic number=90
and mass number =234
number of neutrons =234-90 =144


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