1.

Calculate the number of moles of methanol in 5 litres of its 2 m solution, if the density of the solution is "0.981 kg L"^(-1) (Molar mass of methanol = "32.0 g mol"^(-1))

Answer»


Solution :2 m solution of METHANOL means 2 moles of of methanol in 1000 g of the solvent (water).
2 moles of `CH_(3)OH=2xx32 g=64g`
`THEREFORE"Mass of solution "=1000+64 = 1064 g = 1.064 g""therefore"Volume of solution "=(1.064)/(0.981)=1.085L`
Thus, 1.085 L of the solution contain `CH_(3)OH ` = 2 moles
`therefore " 5 L of the solution will contain " CH_(3)OH=(2)/(1.085)XX5="9.22 moles"`


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