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Calculate the number of moles of KMnO_(4) neededto react completelywith one mole of ferrous oxalate in acidic medium. |
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Answer» Solution :`2KMnO_(4)+ 3H_(2)SO_(4) rarr K_(2)SO_(4)+ 2MnSO_(4) +3H_(2)O+ 5(O)] xx3` `FeC_(2)O_(4)+ H_(2)SO_(4) rarr FeSO_(4)+ H_(2)C_(2)O_(4)] xx 10` ` 2FeSO_(4)+ H_(2)SO_(4) + (O) rarr Fe_(2)(SO_(4))_(3)+ H_(2)O] xx 5` `H_(2)C_(2)O_(4) + (O) rarr 2CO_(2)+ H_(2)O] xx 10` `bar (6 KMnO_(4) + 24 H_(2)SO_(4) + 10 FeC_(2)O_(4) rarr 3K_(2)SO_(4) + 6 MnSO_(4) + 5Fe_(2)(SO_(4))_(3)+ 20 CO_(2)+ 24 H_(2)O)` Thus, 10 MOLES of ferrous oxalate reacts with 6 moles of `KMnO_(4)` `:. ` 1 mole of ferrous oxalate will react with `KMnO_(4)= ( 6)/(10) ` mole `= (3)/( 5) ` mole |
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