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Calculate the number of moles in a)80.5 grams of K2IRCL6 b) 3.10 grams of calcium phosphate [K=39 , Ir =192 Ca=40 , P=31marking the best answer brainiest​

Answer»

moles = Given weight/Molecular mass(a) Given weight = 80.5gMolecular mass of K2IrCl6= k2 + IR + CL6= (39 x 2) + 192 + (35.4 x 6)= 78 + 192 + 212.4= 482.4 uNo. of moles = 80.5/482.4 = 0.16 Moles.(b)Given weight = 3.10gMolecular mass of Ca3(PO4)2= Ca3 + (PO4)2= (40 x 3) + (31 + 16 x 4)2= 120 + 95 x 2= 120 + 190= 310 uNo. of moles = 3.10/310 = 0.01 Moles.



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