1.

Calculate the number of millilitres at STP of H_(2)S gas needed to precipitate cupric sulphide completely from 100mL of a solution containing 0.75 g of CuCl_(2) in 1L.

Answer»

21.4
14.2
41.2
124

Solution :`CuCl_(2)+H_(2)srarrCuS+2HCl`
NUMBER of MOLES of `H_(2)S`=Number of moles of `CuCl_(2)`
`=(0.75)/(134.5)=0.00557`
Volume of `H_(2)S=0.00557xx22400=124.8mL`.


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