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Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of `10.0 g`. Silver has 47 electrins per atom, and its molar mass is `107.87 gmol^(-1)`. |
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Answer» Correct Answer - `2.62xx10^(24)` Number of atoms in 10g of silver is `n=(6.023xx10^(23)xx10)/(107.87)=5.58xx10^(22)` Number of electrons is `47n=2.62xx10^(24)`. |
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