Calculate the number of Cl- and Ca2+ ions in 333 g anhydrous CaCl2. – InterviewSolution

1.

Calculate the number of Cl- and Ca2+ ions in 333 g anhydrous CaCl2.

Answer»

Mol. wt. of CaCl₂ = 111 g

111 g CaCl₂ has = N ions of Ca²⁺

333 g CaCl₂ has N x 333/111 ions of Ca²⁺ = 3 N ions of Ca²⁺

Also, 111 g CaCI₂ has = 2 N ions of Cl^-

333 g CaCl₂ has = 2N x 333/111 ions of Cl^-

= 6 N ions of CI^-

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