Calculate the number of atoms present in 52 moles of He52 amu He52g He

1.	Calculate the number of atoms present in 52 moles of He52 amu He52g He
Answer» Hii There!!! 1) 1 mole of He contains 6.023x10^23 So, 52 moles of He contains 52 x 6.023 x10^23atoms 2) Atomic mass of HELIUM is 4u = 2protons + 2 NEUTRONS = 1 atom So, The number of ATOMS in 52u = 52/4 = 13 atoms. 3) 4g of He has 1 mole =) 1g of He has 1/4 mole So, 52g of He has 1/4 x 52 = 13 moles Since, 1 mole=6.022x10^23atoms So, 13 moles 13x6.023x10^23 atoms. Hope it helps☺️

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