1.

Calculate the number of atoms of each elementpresent in 122.5g of KCIO_(3).

Answer»

Solution :NUMBER of ATOM of 'K'=`1xx6.023xx10^(23)`
Number of ATOMS of 'Cl'`=1xx6.023xx10^(23)`
Number of atoms of 'O'`=3xx6.023xx10^(23)`


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