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Calculate the number of `alpha`- and `beta`-particles emitted when `._(92)U^(238)` into radioactive `._(82)Pb^(206)`. |
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Answer» Parent element =`._(92)U^(238)`, daughter element =`._(82)Pb^(206)`. Let `x alpha-` and `y beta`- Particles be given out during the change `._(92)U^(238) rarr ._(82)Pb^(206) + x_(2)He^(4) + y ._(-1)e^(0)` Equating mass number on both sides `238 = 206 + 4x y xx 0` or `x = 8` Equating atomic number on both sides `92 = 82 + 2x + y (-1)` `= 82 + 2 xx 8 + y (-1)` or `y = 6` `:.` Number of `alpha`-particles = 8, Number of `beta- particles = 6 |
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