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Calculate the normality of the solution obtained by mixing (ii) 100 cc of 0.1 N H_(2)SO_(4) with 100 cc of 0.2 N NaOH. |
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Answer» Solution :100 cc of of 0.1 N `H_(2)SO_(4)=100xx0.1` meq = 10 meq , 100 cc of 0.2 N NaOH `=100xx0.2" meq = 20 meq"` 10 meq of `H_(2)SO_(4)` will NEUTRALIZE 10 meq of NaOH `THEREFORE` meq of NaOH left after neutralisation = 10 meq TOTAL volume of the solution `=100+100="200cc " therefore" NORMALITY of NaOH in the solution "=("10 meq.")/("200 cc")=0.05N.` |
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