1.

Calculate the normality of the solution obtained by mixing 100 cc of 0.2 N H_(2)SO_(4) with 50 cc of 0.1 N HCl.

Answer»

Solution :100 cc of 0.2 N `H_(2)SO_(4)=100x0.2" meq. = 20 meq."`
`"50 cc of 0.1 N HCL cotains HCl "=50xx0.1" meq.= 5 meq."`
Total volume of the solution of the solution after MIXING `=100+50="150 cc"`
`therefore"Normality of the final solution"=("25 meq")/("150 cc")="0.167 N."`
Alternatively `""N_(1)V_(1)+N_(2)V_(2)=N_(3)V_(3)`
`0.2xx100+0.1xx50=N_(3)(100+50) or 150 N_(3)=20+5=25"or"N_(3)=(25)/(150)="0.167 N."`


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