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Calculate the normality of KOH solution containing 11.2g of KOH in 10litere |
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Answer» 13Explanation:Molarity of KOH solution = weight /MOLECULAR weight × volume =5.6/56 x 1 =0.1MThis is EQUAL to [OH - )pOH=−log[OH − ]=−log(0.1)=1 pH=14−pOH=14−1=13. |
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