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Calculate the no. of moles in 0.31 g of sodium oxide |
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Answer» ong>Step-by-step explanation: The molecular mass of natrium OXIDE is 61.98
g ⋅ m o l − 1 . If
m o l natrium react, then 5 2
m o l × 61.98
g ⋅ m o l − 1
=
154.95
g natrium oxide should result. So what have I DONE here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the MOLAR quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go. |
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