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Calculate the no. of molecule & oxygen atoms present in O^9 gram of water |
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Answer» Answer: How many MOLECULES of water and OXYGEN atoms are present in 0.9g of water? Atomic Mass of H = 1 a.m.u Atomic Mass of O = 16 a.m.u Therefore Relative Molecular Mass of Water ( H2O ) is 1(2) + 16(1) = 2 + 16 = 18 Therefore, 1 mole of Water contains 18 G of Water. 0.9 g of Water hence contains 0.05 moles of Water. Avogadro's Number = 6.023×1023 Hence, 1 mole of Water contains 6.023×1023 molecules of Water. Therefore, 0.05 moles contains 0.05×6.023×1023 molecules which is 3.0115×1022 molecules. For the SECOND part of your question, the number of water molecules equals the number of atoms of oxygen since each water molecule contains only 1 oxygen atom. Therefore, the number of oxygen atoms is same which is 3.0115×1022 Explanation: PLEASE mark as brainliest answer and follow me please and thank me please Because I am a very good boy |
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