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Calculate the no of electrons present in 1.6 grms of mg |
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Answer» 24 grms of My CONTAIN = 6.022* 10²³ atoms 1 GRM will contain =1/24 *6.022*10²³ 1.6 grs contain ( 1.6 *6.022*10²³)/24 = 0.4015*10²³ atoms now 1 atom of my contain 12 electrons so no. of electrons in 0.4015 *10²³ atoms of Mg. = 0.4015 *10²³ *12 =4.818 *10²³ |
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