1.

Calculate the no. of disintegrations which 1 g of radioactive element ""^(200)X undergoes per sec. t_(1//2) of X =1000 years.

Answer»

`3.66 xx 10^(10)` DPS
`6.6 xx 10^(10) ` dps
`10^(11)` dps
`1.0 xx 10^(10)` dps

Solution :`-(dN)/(dt) = KN`
`= (0.693)/(1000 xx 365 xx 24 xx 60 xx 60) xx (6.02 xx 10^(23))/(200)`
`-6.6 xx 10^(10)` dps.


Discussion

No Comment Found

Related InterviewSolutions