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Calculate the mutual inducatnce between two coils when a current of `2A` changes to `6A` in `2` seconds and induces an emf of `20 mV` in the secondary coil |
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Answer» `|e| = M(dI)/(dt)` `20 xx 10^(-3) = M((6-2))/(2)` (or) `M = 10mH` |
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