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Calculate the mole fraction of NaOH in a solution containing 20 g of NaOH per 360 g of water. |
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Answer» Number of moles of NaoH = \(\frac{20g}{40\,g\,mol^{-1}}\) = 0.5 Number of moles of water = \(\frac{360g}{18\,g\,mol^{-1}}\) = 20 Total number of moles = 20.5 mole fraction of NoaH = \(\frac{0.5}{20.5}\) = 0.0244 |
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